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7p^2+31p+12=0
a = 7; b = 31; c = +12;
Δ = b2-4ac
Δ = 312-4·7·12
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-25}{2*7}=\frac{-56}{14} =-4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+25}{2*7}=\frac{-6}{14} =-3/7 $
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